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x^2+5x+6=4x+3
We move all terms to the left:
x^2+5x+6-(4x+3)=0
We get rid of parentheses
x^2+5x-4x-3+6=0
We add all the numbers together, and all the variables
x^2+x+3=0
a = 1; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·1·3
Δ = -11
Delta is less than zero, so there is no solution for the equation
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